Base | Representation |
---|---|
bin | 111101100000110… |
… | …011110101111011 |
3 | 2122220220121010111 |
4 | 331200303311323 |
5 | 4103143324011 |
6 | 250223325151 |
7 | 34400643544 |
oct | 7540636573 |
9 | 2586817114 |
10 | 1032011131 |
11 | 48a5a8268 |
12 | 2497507b7 |
13 | 135a67698 |
14 | 9b0c14cb |
15 | 60906121 |
hex | 3d833d7b |
1032011131 has 2 divisors, whose sum is σ = 1032011132. Its totient is φ = 1032011130.
The previous prime is 1032011093. The next prime is 1032011179. The reversal of 1032011131 is 1311102301.
It is a weak prime.
It is an emirp because it is prime and its reverse (1311102301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1032011131 is a prime.
It is a super-2 number, since 2×10320111312 = 2130093949015798322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1032011831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516005565 + 516005566.
It is an arithmetic number, because the mean of its divisors is an integer number (516005566).
Almost surely, 21032011131 is an apocalyptic number.
1032011131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032011131 is an equidigital number, since it uses as much as digits as its factorization.
1032011131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
The square root of 1032011131 is about 32124.9300543986. The cubic root of 1032011131 is about 1010.5585026606.
Adding to 1032011131 its reverse (1311102301), we get a palindrome (2343113432).
The spelling of 1032011131 in words is "one billion, thirty-two million, eleven thousand, one hundred thirty-one".
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