Base | Representation |
---|---|
bin | 10111011101110001100110… |
… | …111111011111111000011011 |
3 | 111112101221100012212000010001 |
4 | 113131301212333133320123 |
5 | 102011322030220004404 |
6 | 1003253551105433431 |
7 | 30511016665130221 |
oct | 2735614677377033 |
9 | 445357305760101 |
10 | 103201202109979 |
11 | 2a979425161076 |
12 | b6a910193b877 |
13 | 4577aa704799c |
14 | 1b6ad71708b11 |
15 | bde777c8d7a4 |
hex | 5ddc66fdfe1b |
103201202109979 has 2 divisors, whose sum is σ = 103201202109980. Its totient is φ = 103201202109978.
The previous prime is 103201202109961. The next prime is 103201202110081. The reversal of 103201202109979 is 979901202102301.
It is a weak prime.
It is an emirp because it is prime and its reverse (979901202102301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103201202109979 - 231 = 103199054626331 is a prime.
It is a super-2 number, since 2×1032012021099792 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103201202109919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51600601054989 + 51600601054990.
It is an arithmetic number, because the mean of its divisors is an integer number (51600601054990).
Almost surely, 2103201202109979 is an apocalyptic number.
103201202109979 is a deficient number, since it is larger than the sum of its proper divisors (1).
103201202109979 is an equidigital number, since it uses as much as digits as its factorization.
103201202109979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 46.
The spelling of 103201202109979 in words is "one hundred three trillion, two hundred one billion, two hundred two million, one hundred nine thousand, nine hundred seventy-nine".
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