10320131333333 has 4 divisors (see below), whose sum is σ = 10320195143808. Its totient is φ = 10320067522860.

The previous prime is 10320131333299. The next prime is 10320131333359. The reversal of 10320131333333 is 33333313102301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10320131333333 - 2¹² = 10320131329237 is a prime.

It is a super-2 number, since 2×10320131333333² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10320131333296 and 10320131333305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10320131333233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31662023 + ... + 31986308.

It is an arithmetic number, because the mean of its divisors is an integer number (2580048785952).

Almost surely, 2^{10320131333333} is an apocalyptic number.

It is an amenable number.

10320131333333 is a deficient number, since it is larger than the sum of its proper divisors (63810475).

10320131333333 is an equidigital number, since it uses as much as digits as its factorization.

10320131333333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63810474.

The product of its (nonzero) digits is 13122, while the sum is 29.

Adding to 10320131333333 its reverse (33333313102301), we get a palindrome (43653444435634).

The spelling of 10320131333333 in words is "ten trillion, three hundred twenty billion, one hundred thirty-one million, three hundred thirty-three thousand, three hundred thirty-three".