Base | Representation |
---|---|
bin | 110000000011101011… |
… | …0010110000011101011 |
3 | 100212101100201212101011 |
4 | 1200013112112003223 |
5 | 3142324320410011 |
6 | 115224404004351 |
7 | 10312311613324 |
oct | 1400726260353 |
9 | 325340655334 |
10 | 103202513131 |
11 | 3a84a145673 |
12 | 180023906b7 |
13 | 996914b123 |
14 | 4dd050144b |
15 | 2a40482621 |
hex | 18075960eb |
103202513131 has 2 divisors, whose sum is σ = 103202513132. Its totient is φ = 103202513130.
The previous prime is 103202513093. The next prime is 103202513149. The reversal of 103202513131 is 131315202301.
It is a strong prime.
It is an emirp because it is prime and its reverse (131315202301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103202513131 - 213 = 103202504939 is a prime.
It is a super-2 number, since 2×1032025131312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103202513171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51601256565 + 51601256566.
It is an arithmetic number, because the mean of its divisors is an integer number (51601256566).
Almost surely, 2103202513131 is an apocalyptic number.
103202513131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103202513131 is an equidigital number, since it uses as much as digits as its factorization.
103202513131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 103202513131 its reverse (131315202301), we get a palindrome (234517715432).
The spelling of 103202513131 in words is "one hundred three billion, two hundred two million, five hundred thirteen thousand, one hundred thirty-one".
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