103204341344311 has 4 divisors (see below), whose sum is σ = 104618099444992. Its totient is φ = 101790583243632.

The previous prime is 103204341344309. The next prime is 103204341344327. The reversal of 103204341344311 is 113443143402301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103204341344311 - 2¹ = 103204341344309 is a prime.

It is a super-4 number, since 4×103204341344311⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103204341324311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 706879050231 + ... + 706879050376.

It is an arithmetic number, because the mean of its divisors is an integer number (26154524861248).

Almost surely, 2^{103204341344311} is an apocalyptic number.

103204341344311 is a deficient number, since it is larger than the sum of its proper divisors (1413758100681).

103204341344311 is an equidigital number, since it uses as much as digits as its factorization.

103204341344311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1413758100680.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 103204341344311 its reverse (113443143402301), we get a palindrome (216647484746612).

The spelling of 103204341344311 in words is "one hundred three trillion, two hundred four billion, three hundred forty-one million, three hundred forty-four thousand, three hundred eleven".