Base | Representation |
---|---|
bin | 11110000010011100001… |
… | …01011111001000100011 |
3 | 10122200000222101202202201 |
4 | 33001032011133020203 |
5 | 113402221131242011 |
6 | 2110050300154031 |
7 | 134365312024144 |
oct | 17011605371043 |
9 | 3580028352681 |
10 | 1032102212131 |
11 | 368791879021 |
12 | 148040b38917 |
13 | 76433044633 |
14 | 37d4db55acb |
15 | 1bca9be2cc1 |
hex | f04e15f223 |
1032102212131 has 2 divisors, whose sum is σ = 1032102212132. Its totient is φ = 1032102212130.
The previous prime is 1032102212111. The next prime is 1032102212179. The reversal of 1032102212131 is 1312122012301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1032102212131 - 215 = 1032102179363 is a prime.
It is a super-2 number, since 2×10321022121312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1032102212099 and 1032102212108.
It is not a weakly prime, because it can be changed into another prime (1032102212101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516051106065 + 516051106066.
It is an arithmetic number, because the mean of its divisors is an integer number (516051106066).
Almost surely, 21032102212131 is an apocalyptic number.
1032102212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032102212131 is an equidigital number, since it uses as much as digits as its factorization.
1032102212131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1032102212131 its reverse (1312122012301), we get a palindrome (2344224224432).
The spelling of 1032102212131 in words is "one trillion, thirty-two billion, one hundred two million, two hundred twelve thousand, one hundred thirty-one".
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