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103222131300 = 223452101126173
BaseRepresentation
bin110000000100010000…
…1001011101001100100
3100212102201122120110000
41200020201023221210
53142344331200200
6115230344301300
710312640432211
oct1401041135144
9325381576400
10103222131300
113a85a225032
1218008a71830
139970229802
144dd2d6ab08
152a4205a300
hex180884ba64

103222131300 has 180 divisors, whose sum is σ = 337920973236. Its totient is φ = 27253152000.

The previous prime is 103222131277. The next prime is 103222131323. The reversal of 103222131300 is 3131222301.

103222131300 is a `hidden beast` number, since 1 + 0 + 322 + 213 + 130 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (103222131277) and next prime (103222131323).

It can be written as a sum of positive squares in 6 ways, for example, as 11573604 + 103210557696 = 3402^2 + 321264^2 .

It is a tau number, because it is divible by the number of its divisors (180).

It is a super-3 number, since 3×1032221313003 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 755014 + ... + 881186.

Almost surely, 2103222131300 is an apocalyptic number.

103222131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103222131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168960486618).

103222131300 is an abundant number, since it is smaller than the sum of its proper divisors (234698841936).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103222131300 is a wasteful number, since it uses less digits than its factorization.

103222131300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 126300 (or 126284 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 103222131300 its reverse (3131222301), we get a palindrome (106353353601).

The spelling of 103222131300 in words is "one hundred three billion, two hundred twenty-two million, one hundred thirty-one thousand, three hundred".