Base | Representation |
---|---|
bin | 110000000100010110… |
… | …1110100101100001011 |
3 | 100212102221212221011111 |
4 | 1200020231310230023 |
5 | 3142401203221011 |
6 | 115230543311151 |
7 | 10313010543424 |
oct | 1401055645413 |
9 | 325387787144 |
10 | 103225445131 |
11 | 3a861088836 |
12 | 18009bab4b7 |
13 | 9970b19c63 |
14 | 4dd359064b |
15 | 2a424b2121 |
hex | 1808b74b0b |
103225445131 has 2 divisors, whose sum is σ = 103225445132. Its totient is φ = 103225445130.
The previous prime is 103225445111. The next prime is 103225445231. The reversal of 103225445131 is 131544522301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103225445131 - 225 = 103191890699 is a prime.
It is a super-2 number, since 2×1032254451312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103225445093 and 103225445102.
It is not a weakly prime, because it can be changed into another prime (103225445111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51612722565 + 51612722566.
It is an arithmetic number, because the mean of its divisors is an integer number (51612722566).
Almost surely, 2103225445131 is an apocalyptic number.
103225445131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103225445131 is an equidigital number, since it uses as much as digits as its factorization.
103225445131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 103225445131 its reverse (131544522301), we get a palindrome (234769967432).
The spelling of 103225445131 in words is "one hundred three billion, two hundred twenty-five million, four hundred forty-five thousand, one hundred thirty-one".
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