Base | Representation |
---|---|
bin | 10011001110100110… |
… | …10100001000101111 |
3 | 222122102122022212021 |
4 | 21213103110020233 |
5 | 132120200113210 |
6 | 4424202451011 |
7 | 513546325522 |
oct | 114723241057 |
9 | 28572568767 |
10 | 10323051055 |
11 | 4418103059 |
12 | 2001203a67 |
13 | c868c9345 |
14 | 6dd016bb9 |
15 | 406421bda |
hex | 2674d422f |
10323051055 has 4 divisors (see below), whose sum is σ = 12387661272. Its totient is φ = 8258440840.
The previous prime is 10323051043. The next prime is 10323051073. The reversal of 10323051055 is 55015032301.
10323051055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 10323051055 - 215 = 10323018287 is a prime.
It is a super-2 number, since 2×103230510552 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1032305101 + ... + 1032305110.
It is an arithmetic number, because the mean of its divisors is an integer number (3096915318).
Almost surely, 210323051055 is an apocalyptic number.
10323051055 is a deficient number, since it is larger than the sum of its proper divisors (2064610217).
10323051055 is an equidigital number, since it uses as much as digits as its factorization.
10323051055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2064610216.
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 10323051055 its reverse (55015032301), we get a palindrome (65338083356).
The spelling of 10323051055 in words is "ten billion, three hundred twenty-three million, fifty-one thousand, fifty-five".
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