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1032311313139 is a prime number
BaseRepresentation
bin11110000010110101000…
…11001001001011110011
310122200120112212012102111
433001122203021023303
5113403133144010024
62110123130030151
7134403431245111
oct17013243111363
93580515765374
101032311313139
11368889907777
1214809ab78357
1376467467242
1437d6d826ab1
151bcbd248a94
hexf05a8c92f3

1032311313139 has 2 divisors, whose sum is σ = 1032311313140. Its totient is φ = 1032311313138.

The previous prime is 1032311313119. The next prime is 1032311313149. The reversal of 1032311313139 is 9313131132301.

1032311313139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1032311313139 - 25 = 1032311313107 is a prime.

It is a super-3 number, since 3×10323113131393 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1032311313139.

It is not a weakly prime, because it can be changed into another prime (1032311313119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516155656569 + 516155656570.

It is an arithmetic number, because the mean of its divisors is an integer number (516155656570).

Almost surely, 21032311313139 is an apocalyptic number.

1032311313139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1032311313139 is an equidigital number, since it uses as much as digits as its factorization.

1032311313139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4374, while the sum is 31.

The spelling of 1032311313139 in words is "one trillion, thirty-two billion, three hundred eleven million, three hundred thirteen thousand, one hundred thirty-nine".