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103231231314131 is a prime number
BaseRepresentation
bin10111011110001101100100…
…110111110100100011010011
3111112111210212000002122001102
4113132031210313310203103
5102012320030204023011
61003315434543455015
730513132101141324
oct2736154467644323
9445453760078042
10103231231314131
112a990134931668
12b6b2aa25b746b
13457a88149673b
141b6c5bd99644b
15be043423573b
hex5de364df48d3

103231231314131 has 2 divisors, whose sum is σ = 103231231314132. Its totient is φ = 103231231314130.

The previous prime is 103231231314077. The next prime is 103231231314137. The reversal of 103231231314131 is 131413132132301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103231231314131 - 26 = 103231231314067 is a prime.

It is a super-2 number, since 2×1032312313141312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103231231314094 and 103231231314103.

It is not a weakly prime, because it can be changed into another prime (103231231314137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51615615657065 + 51615615657066.

It is an arithmetic number, because the mean of its divisors is an integer number (51615615657066).

Almost surely, 2103231231314131 is an apocalyptic number.

103231231314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

103231231314131 is an equidigital number, since it uses as much as digits as its factorization.

103231231314131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 103231231314131 its reverse (131413132132301), we get a palindrome (234644363446432).

The spelling of 103231231314131 in words is "one hundred three trillion, two hundred thirty-one billion, two hundred thirty-one million, three hundred fourteen thousand, one hundred thirty-one".