1032321300113 has 2 divisors, whose sum is σ = 1032321300114. Its totient is φ = 1032321300112.

The previous prime is 1032321300089. The next prime is 1032321300139. The reversal of 1032321300113 is 3110031232301.

1032321300113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 540125044624 + 492196255489 = 734932^2 + 701567^2 .

It is a cyclic number.

It is not a de Polignac number, because 1032321300113 - 2¹⁴ = 1032321283729 is a prime.

It is a super-2 number, since 2×1032321300113² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1032321300163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516160650056 + 516160650057.

It is an arithmetic number, because the mean of its divisors is an integer number (516160650057).

Almost surely, 2^{1032321300113} is an apocalyptic number.

It is an amenable number.

1032321300113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1032321300113 is an equidigital number, since it uses as much as digits as its factorization.

1032321300113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1032321300113 its reverse (3110031232301), we get a palindrome (4142352532414).

The spelling of 1032321300113 in words is "one trillion, thirty-two billion, three hundred twenty-one million, three hundred thousand, one hundred thirteen".