Base | Representation |
---|---|
bin | 10111011110001111010110… |
… | …001010110010010010100100 |
3 | 111112111222202110210010011220 |
4 | 113132033112022302102210 |
5 | 102012332423310023022 |
6 | 1003320351324300340 |
7 | 30513230151510231 |
oct | 2736172612622244 |
9 | 445458673703156 |
10 | 103233132111012 |
11 | 2a990a1a881482 |
12 | b6b33330a16b0 |
13 | 457aac5218c17 |
14 | 1b6c7201ca788 |
15 | be04e604e85c |
hex | 5de3d62b24a4 |
103233132111012 has 24 divisors (see below), whose sum is σ = 243583794871200. Its totient is φ = 34024403092416.
The previous prime is 103233132110971. The next prime is 103233132111049. The reversal of 103233132111012 is 210111231332301.
It is a super-2 number, since 2×1032331321110122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48330116962 + ... + 48330119097.
It is an arithmetic number, because the mean of its divisors is an integer number (10149324786300).
Almost surely, 2103233132111012 is an apocalyptic number.
103233132111012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
103233132111012 is an abundant number, since it is smaller than the sum of its proper divisors (140350662760188).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103233132111012 is a wasteful number, since it uses less digits than its factorization.
103233132111012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96660236155 (or 96660236153 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 103233132111012 its reverse (210111231332301), we get a palindrome (313344363443313).
The spelling of 103233132111012 in words is "one hundred three trillion, two hundred thirty-three billion, one hundred thirty-two million, one hundred eleven thousand, twelve".
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