Base | Representation |
---|---|
bin | 110000000100110100… |
… | …1111101100010111001 |
3 | 100212111001112212120001 |
4 | 1200021221331202321 |
5 | 3142414222210131 |
6 | 115232305233001 |
7 | 10313261543314 |
oct | 1401151754271 |
9 | 325431485501 |
10 | 103241210041 |
11 | 3a869a76192 |
12 | 18013332761 |
13 | 99741797c8 |
14 | 4dd56d597b |
15 | 2a43a78261 |
hex | 1809a7d8b9 |
103241210041 has 2 divisors, whose sum is σ = 103241210042. Its totient is φ = 103241210040.
The previous prime is 103241210029. The next prime is 103241210057. The reversal of 103241210041 is 140012142301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100761170041 + 2480040000 = 317429^2 + 49800^2 .
It is an emirp because it is prime and its reverse (140012142301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103241210041 - 233 = 94651275449 is a prime.
It is not a weakly prime, because it can be changed into another prime (103241211041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51620605020 + 51620605021.
It is an arithmetic number, because the mean of its divisors is an integer number (51620605021).
Almost surely, 2103241210041 is an apocalyptic number.
It is an amenable number.
103241210041 is a deficient number, since it is larger than the sum of its proper divisors (1).
103241210041 is an equidigital number, since it uses as much as digits as its factorization.
103241210041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 103241210041 its reverse (140012142301), we get a palindrome (243253352342).
The spelling of 103241210041 in words is "one hundred three billion, two hundred forty-one million, two hundred ten thousand, forty-one".
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