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10325211130042 = 25162605565021
BaseRepresentation
bin1001011001000000011010…
…0010101010100010111010
31100120002011201100101100121
42112100012202222202322
52323132013022130132
633543200404123454
72113654233342544
oct226200642524272
940502151311317
1010325211130042
113320996561486
1211a911839658a
1359b881173953
14279a58696694
1512d8b0acb497
hex964068aa8ba

10325211130042 has 4 divisors (see below), whose sum is σ = 15487816695066. Its totient is φ = 5162605565020.

The previous prime is 10325211130037. The next prime is 10325211130057. The reversal of 10325211130042 is 24003111252301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9527599595761 + 797611534281 = 3086681^2 + 893091^2 .

It is a junction number, because it is equal to n+sod(n) for n = 10325211129989 and 10325211130016.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2581302782509 + ... + 2581302782512.

Almost surely, 210325211130042 is an apocalyptic number.

10325211130042 is a deficient number, since it is larger than the sum of its proper divisors (5162605565024).

10325211130042 is an equidigital number, since it uses as much as digits as its factorization.

10325211130042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5162605565023.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 10325211130042 its reverse (24003111252301), we get a palindrome (34328322382343).

The spelling of 10325211130042 in words is "ten trillion, three hundred twenty-five billion, two hundred eleven million, one hundred thirty thousand, forty-two".

Divisors: 1 2 5162605565021 10325211130042