Base | Representation |
---|---|
bin | 110000000101001111… |
… | …1101101110001111001 |
3 | 100212112001001210001100 |
4 | 1200022133231301321 |
5 | 3142431324114431 |
6 | 115233531242013 |
7 | 10313522402451 |
oct | 1401237556171 |
9 | 325461053040 |
10 | 103255301241 |
11 | 3a876a20104 |
12 | 18017ba9309 |
13 | 99770715b1 |
14 | 4dd7522d61 |
15 | 2a44e0d4e6 |
hex | 180a7edc79 |
103255301241 has 48 divisors (see below), whose sum is σ = 165865939200. Its totient is φ = 61625297664.
The previous prime is 103255301189. The next prime is 103255301249. The reversal of 103255301241 is 142103552301.
103255301241 is a `hidden beast` number, since 1 + 0 + 3 + 2 + 5 + 530 + 124 + 1 = 666.
It is not a de Polignac number, because 103255301241 - 213 = 103255293049 is a prime.
It is a super-2 number, since 2×1032553012412 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (103255301249) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11565 + ... + 454581.
It is an arithmetic number, because the mean of its divisors is an integer number (3455540400).
Almost surely, 2103255301241 is an apocalyptic number.
It is an amenable number.
103255301241 is a deficient number, since it is larger than the sum of its proper divisors (62610637959).
103255301241 is a wasteful number, since it uses less digits than its factorization.
103255301241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 443118 (or 443115 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 103255301241 its reverse (142103552301), we get a palindrome (245358853542).
It can be divided in two parts, 103255 and 301241, that added together give a square (404496 = 6362).
The spelling of 103255301241 in words is "one hundred three billion, two hundred fifty-five million, three hundred one thousand, two hundred forty-one".
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