Base | Representation |
---|---|
bin | 110000000110100101… |
… | …0001111101010010001 |
3 | 100212122011011221101111 |
4 | 1200031022033222101 |
5 | 3143024300120442 |
6 | 115242205333321 |
7 | 10314604356604 |
oct | 1401512175221 |
9 | 325564157344 |
10 | 103300004497 |
11 | 3a89a183348 |
12 | 1802ab67241 |
13 | 99833c3b21 |
14 | 4ddd43c33b |
15 | 2a48cddb17 |
hex | 180d28fa91 |
103300004497 has 2 divisors, whose sum is σ = 103300004498. Its totient is φ = 103300004496.
The previous prime is 103300004389. The next prime is 103300004531. The reversal of 103300004497 is 794400003301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70713978241 + 32586026256 = 265921^2 + 180516^2 .
It is an emirp because it is prime and its reverse (794400003301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103300004497 - 219 = 103299480209 is a prime.
It is not a weakly prime, because it can be changed into another prime (103300007497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51650002248 + 51650002249.
It is an arithmetic number, because the mean of its divisors is an integer number (51650002249).
Almost surely, 2103300004497 is an apocalyptic number.
It is an amenable number.
103300004497 is a deficient number, since it is larger than the sum of its proper divisors (1).
103300004497 is an equidigital number, since it uses as much as digits as its factorization.
103300004497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 103300004497 its reverse (794400003301), we get a palindrome (897700007798).
The spelling of 103300004497 in words is "one hundred three billion, three hundred million, four thousand, four hundred ninety-seven".
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