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103300120322112 = 2637434918394339
BaseRepresentation
bin10111011111001101101110…
…111110100010000001000000
3111112202101122222220211101110
4113133031232332202001000
5102014432121300301422
61003411230430203320
730521121165064230
oct2737155676420100
9445671588824343
10103300120322112
112aa07375990a0a
12b704309353540
13458420c6b215c
141b71a76c0bcc0
15be211703d60c
hex5df36efa2040

103300120322112 has 448 divisors, whose sum is σ = 320730671923200. Its totient is φ = 28728315463680.

The previous prime is 103300120322099. The next prime is 103300120322173. The reversal of 103300120322112 is 211223021003301.

It is a tau number, because it is divible by the number of its divisors (448).

It is a super-2 number, since 2×1033001203221122 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23807354439 + ... + 23807358777.

It is an arithmetic number, because the mean of its divisors is an integer number (715916678400).

Almost surely, 2103300120322112 is an apocalyptic number.

103300120322112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103300120322112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (160365335961600).

103300120322112 is an abundant number, since it is smaller than the sum of its proper divisors (217430551601088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103300120322112 is a wasteful number, since it uses less digits than its factorization.

103300120322112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5734 (or 5724 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 103300120322112 its reverse (211223021003301), we get a palindrome (314523141325413).

The spelling of 103300120322112 in words is "one hundred three trillion, three hundred billion, one hundred twenty million, three hundred twenty-two thousand, one hundred twelve".