Search a number
-
+
103301114302 = 251650557151
BaseRepresentation
bin110000000110100111…
…0011110100110111110
3100212122020021022202101
41200031032132212332
53143030041124202
6115242245215314
710314616661311
oct1401516364676
9325566238671
10103301114302
113a89a871141
121802b40153a
1399836c2009
144ddd64a978
152a48e5c887
hex180d39e9be

103301114302 has 4 divisors (see below), whose sum is σ = 154951671456. Its totient is φ = 51650557150.

The previous prime is 103301114233. The next prime is 103301114309. The reversal of 103301114302 is 203411103301.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1033011143022 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 103301114302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103301114309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25825278574 + ... + 25825278577.

It is an arithmetic number, because the mean of its divisors is an integer number (38737917864).

Almost surely, 2103301114302 is an apocalyptic number.

103301114302 is a deficient number, since it is larger than the sum of its proper divisors (51650557154).

103301114302 is an equidigital number, since it uses as much as digits as its factorization.

103301114302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51650557153.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 103301114302 its reverse (203411103301), we get a palindrome (306712217603).

The spelling of 103301114302 in words is "one hundred three billion, three hundred one million, one hundred fourteen thousand, three hundred two".

Divisors: 1 2 51650557151 103301114302