Base | Representation |
---|---|
bin | 110000000110111100… |
… | …0011000101100100011 |
3 | 100212122222221110110221 |
4 | 1200031320120230203 |
5 | 3143040344201011 |
6 | 115243320503511 |
7 | 10315112235052 |
oct | 1401570305443 |
9 | 325588843427 |
10 | 103312100131 |
11 | 3a8a5a94a39 |
12 | 1803301ab97 |
13 | 9985a6a4c6 |
14 | 5000caa399 |
15 | 2a49dcc971 |
hex | 180de18b23 |
103312100131 has 2 divisors, whose sum is σ = 103312100132. Its totient is φ = 103312100130.
The previous prime is 103312100123. The next prime is 103312100153. The reversal of 103312100131 is 131001213301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103312100131 - 23 = 103312100123 is a prime.
It is a super-2 number, since 2×1033121001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103312100231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51656050065 + 51656050066.
It is an arithmetic number, because the mean of its divisors is an integer number (51656050066).
Almost surely, 2103312100131 is an apocalyptic number.
103312100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103312100131 is an equidigital number, since it uses as much as digits as its factorization.
103312100131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 103312100131 its reverse (131001213301), we get a palindrome (234313313432).
The spelling of 103312100131 in words is "one hundred three billion, three hundred twelve million, one hundred thousand, one hundred thirty-one".
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