Search a number
-
+
103313002081 is a prime number
BaseRepresentation
bin110000000110111101…
…1110100111001100001
3100212200001122021201111
41200031323310321201
53143041112031311
6115243352103321
710315123012462
oct1401573647141
9325601567644
10103313002081
113a8a6550653
1218033394b41
139985cc4bc3
145001062d69
152a4a009d21
hex180def4e61

103313002081 has 2 divisors, whose sum is σ = 103313002082. Its totient is φ = 103313002080.

The previous prime is 103313002003. The next prime is 103313002109. The reversal of 103313002081 is 180200313301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98094240000 + 5218762081 = 313200^2 + 72241^2 .

It is an emirp because it is prime and its reverse (180200313301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103313002081 - 211 = 103313000033 is a prime.

It is a super-2 number, since 2×1033130020812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103313002181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51656501040 + 51656501041.

It is an arithmetic number, because the mean of its divisors is an integer number (51656501041).

Almost surely, 2103313002081 is an apocalyptic number.

It is an amenable number.

103313002081 is a deficient number, since it is larger than the sum of its proper divisors (1).

103313002081 is an equidigital number, since it uses as much as digits as its factorization.

103313002081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 103313002081 its reverse (180200313301), we get a palindrome (283513315382).

The spelling of 103313002081 in words is "one hundred three billion, three hundred thirteen million, two thousand, eighty-one".