Base | Representation |
---|---|
bin | 110000000110111111… |
… | …1101011110011111001 |
3 | 100212200010112200000222 |
4 | 1200031333223303321 |
5 | 3143041341412213 |
6 | 115243425505425 |
7 | 10315134424151 |
oct | 1401577536371 |
9 | 325603480028 |
10 | 103314013433 |
11 | 3a8a7081484 |
12 | 180337a2275 |
13 | 998628a337 |
14 | 5001247761 |
15 | 2a4a159808 |
hex | 180dfebcf9 |
103314013433 has 2 divisors, whose sum is σ = 103314013434. Its totient is φ = 103314013432.
The previous prime is 103314013409. The next prime is 103314013447. The reversal of 103314013433 is 334310413301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100309658089 + 3004355344 = 316717^2 + 54812^2 .
It is a cyclic number.
It is not a de Polignac number, because 103314013433 - 28 = 103314013177 is a prime.
It is not a weakly prime, because it can be changed into another prime (103314013403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51657006716 + 51657006717.
It is an arithmetic number, because the mean of its divisors is an integer number (51657006717).
Almost surely, 2103314013433 is an apocalyptic number.
It is an amenable number.
103314013433 is a deficient number, since it is larger than the sum of its proper divisors (1).
103314013433 is an equidigital number, since it uses as much as digits as its factorization.
103314013433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 103314013433 its reverse (334310413301), we get a palindrome (437624426734).
The spelling of 103314013433 in words is "one hundred three billion, three hundred fourteen million, thirteen thousand, four hundred thirty-three".
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