Base | Representation |
---|---|
bin | 10011010000100001… |
… | …11111101000011001 |
3 | 222200120001210110211 |
4 | 21220100333220121 |
5 | 132133320014433 |
6 | 4425541211121 |
7 | 514133630344 |
oct | 115020775031 |
9 | 28616053424 |
10 | 10339219993 |
11 | 4426247013 |
12 | 2006700aa1 |
13 | c8a06aa6b |
14 | 70122545b |
15 | 407a678cd |
hex | 26843fa19 |
10339219993 has 2 divisors, whose sum is σ = 10339219994. Its totient is φ = 10339219992.
The previous prime is 10339219967. The next prime is 10339220057. The reversal of 10339219993 is 39991293301.
10339219993 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6634428304 + 3704791689 = 81452^2 + 60867^2 .
It is an emirp because it is prime and its reverse (39991293301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10339219993 - 213 = 10339211801 is a prime.
It is not a weakly prime, because it can be changed into another prime (10339219963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5169609996 + 5169609997.
It is an arithmetic number, because the mean of its divisors is an integer number (5169609997).
Almost surely, 210339219993 is an apocalyptic number.
It is an amenable number.
10339219993 is a deficient number, since it is larger than the sum of its proper divisors (1).
10339219993 is an equidigital number, since it uses as much as digits as its factorization.
10339219993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 354294, while the sum is 49.
The spelling of 10339219993 in words is "ten billion, three hundred thirty-nine million, two hundred nineteen thousand, nine hundred ninety-three".
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