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103401212014 = 251700606007
BaseRepresentation
bin110000001001100110…
…0010100100001101110
3100212220012121211000001
41200103030110201232
53143231202241024
6115300222454514
710320243541342
oct1402314244156
9325805554001
10103401212014
113a94131a021
1218058a3443a
13999b36b129
14500ca65622
152a52b31244
hex181331486e

103401212014 has 4 divisors (see below), whose sum is σ = 155101818024. Its totient is φ = 51700606006.

The previous prime is 103401212011. The next prime is 103401212017. The reversal of 103401212014 is 410212104301.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (103401212011) and next prime (103401212017).

It is a junction number, because it is equal to n+sod(n) for n = 103401211982 and 103401212000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103401212011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25850303002 + ... + 25850303005.

It is an arithmetic number, because the mean of its divisors is an integer number (38775454506).

Almost surely, 2103401212014 is an apocalyptic number.

103401212014 is a deficient number, since it is larger than the sum of its proper divisors (51700606010).

103401212014 is an equidigital number, since it uses as much as digits as its factorization.

103401212014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51700606009.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 103401212014 its reverse (410212104301), we get a palindrome (513613316315).

The spelling of 103401212014 in words is "one hundred three billion, four hundred one million, two hundred twelve thousand, fourteen".

Divisors: 1 2 51700606007 103401212014