1034051131 has 2 divisors, whose sum is σ = 1034051132. Its totient is φ = 1034051130.

The previous prime is 1034051113. The next prime is 1034051189. The reversal of 1034051131 is 1311504301.

Together with previous prime (1034051113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1311504301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1034051131 - 2²³ = 1025662523 is a prime.

It is a super-2 number, since 2×1034051131² = 2138523483044758322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1034051099 and 1034051108.

It is not a weakly prime, because it can be changed into another prime (1034051111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517025565 + 517025566.

It is an arithmetic number, because the mean of its divisors is an integer number (517025566).

Almost surely, 2^1034051131 is an apocalyptic number.

1034051131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1034051131 is an equidigital number, since it uses as much as digits as its factorization.

1034051131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 1034051131 is about 32156.6654210290. The cubic root of 1034051131 is about 1011.2239290982.

Adding to 1034051131 its reverse (1311504301), we get a palindrome (2345555432).

The spelling of 1034051131 in words is "one billion, thirty-four million, fifty-one thousand, one hundred thirty-one".