Base | Representation |
---|---|
bin | 110000001001101101… |
… | …1100101111100000011 |
3 | 100212220111011012201222 |
4 | 1200103123211330003 |
5 | 3143233213343431 |
6 | 115300444345255 |
7 | 10320322554314 |
oct | 1402333457403 |
9 | 325814135658 |
10 | 103405215491 |
11 | 3a943603986 |
12 | 1805a24522b |
13 | 999c140456 |
14 | 500d3c860b |
15 | 2a5317257b |
hex | 18136e5f03 |
103405215491 has 2 divisors, whose sum is σ = 103405215492. Its totient is φ = 103405215490.
The previous prime is 103405215437. The next prime is 103405215509. The reversal of 103405215491 is 194512504301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103405215491 is a prime.
It is not a weakly prime, because it can be changed into another prime (103405515491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51702607745 + 51702607746.
It is an arithmetic number, because the mean of its divisors is an integer number (51702607746).
Almost surely, 2103405215491 is an apocalyptic number.
103405215491 is a deficient number, since it is larger than the sum of its proper divisors (1).
103405215491 is an equidigital number, since it uses as much as digits as its factorization.
103405215491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
Adding to 103405215491 its reverse (194512504301), we get a palindrome (297917719792).
The spelling of 103405215491 in words is "one hundred three billion, four hundred five million, two hundred fifteen thousand, four hundred ninety-one".
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