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10341342345 = 356803101341
BaseRepresentation
bin10011010000110010…
…00101110010001001
3222200201001121210110
421220121011302021
5132134340423340
64430054504533
7514160650065
oct115031056211
928621047713
1010341342345
114427466624
122007365149
13c8a631aa9
14701618aa5
15407d36680
hex268645c89

10341342345 has 16 divisors (see below), whose sum is σ = 16548743232. Its totient is φ = 5514517440.

The previous prime is 10341342329. The next prime is 10341342371. The reversal of 10341342345 is 54324314301.

10341342345 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10341342345 - 24 = 10341342329 is a prime.

It is a super-2 number, since 2×103413423452 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51375 + ... + 152715.

It is an arithmetic number, because the mean of its divisors is an integer number (1034296452).

Almost surely, 210341342345 is an apocalyptic number.

10341342345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

10341342345 is a deficient number, since it is larger than the sum of its proper divisors (6207400887).

10341342345 is a wasteful number, since it uses less digits than its factorization.

10341342345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108152.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 10341342345 its reverse (54324314301), we get a palindrome (64665656646).

The spelling of 10341342345 in words is "ten billion, three hundred forty-one million, three hundred forty-two thousand, three hundred forty-five".

Divisors: 1 3 5 15 6803 20409 34015 101341 102045 304023 506705 1520115 689422823 2068268469 3447114115 10341342345