Base | Representation |
---|---|
bin | 11110000010110011101100… |
… | …011011000110111010101100 |
3 | 122022211220211101001201211201 |
4 | 132002303230123012322230 |
5 | 114304342112122021330 |
6 | 1145005402240255244 |
7 | 36555251064030403 |
oct | 3602635433067254 |
9 | 568756741051751 |
10 | 132134340423340 |
11 | 3911394a485472 |
12 | 129a062b311524 |
13 | 58962a3cc49c8 |
14 | 248b49c76463a |
15 | 10421b64a5eca |
hex | 782cec6c6eac |
132134340423340 has 96 divisors (see below), whose sum is σ = 287645498300160. Its totient is φ = 50944721043456.
The previous prime is 132134340423329. The next prime is 132134340423353. The reversal of 132134340423340 is 43324043431231.
It is a super-2 number, since 2×1321343404233402 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a self number, because there is not a number n which added to its sum of digits gives 132134340423340.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 480031389 + ... + 480306571.
It is an arithmetic number, because the mean of its divisors is an integer number (2996307273960).
Almost surely, 2132134340423340 is an apocalyptic number.
132134340423340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132134340423340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (143822749150080).
132134340423340 is an abundant number, since it is smaller than the sum of its proper divisors (155511157876820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132134340423340 is a wasteful number, since it uses less digits than its factorization.
132134340423340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 281291 (or 281289 counting only the distinct ones).
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 132134340423340 its reverse (43324043431231), we get a palindrome (175458383854571).
The spelling of 132134340423340 in words is "one hundred thirty-two trillion, one hundred thirty-four billion, three hundred forty million, four hundred twenty-three thousand, three hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.109 sec. • engine limits •