Base | Representation |
---|---|
bin | 11110000110010111111… |
… | …01010111010100100001 |
3 | 10122212111011010022211211 |
4 | 33003023331113110201 |
5 | 113421032241342233 |
6 | 2111040015310121 |
7 | 134501534025505 |
oct | 17031375272441 |
9 | 3585434108754 |
10 | 1034214012193 |
11 | 36967593672a |
12 | 14853021b341 |
13 | 766ab70447b |
14 | 380b03d4305 |
15 | 1bd802db5cd |
hex | f0cbf57521 |
1034214012193 has 2 divisors, whose sum is σ = 1034214012194. Its totient is φ = 1034214012192.
The previous prime is 1034214012179. The next prime is 1034214012217. The reversal of 1034214012193 is 3912104124301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 596984931904 + 437229080289 = 772648^2 + 661233^2 .
It is a cyclic number.
It is not a de Polignac number, because 1034214012193 - 229 = 1033677141281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1034214082193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517107006096 + 517107006097.
It is an arithmetic number, because the mean of its divisors is an integer number (517107006097).
Almost surely, 21034214012193 is an apocalyptic number.
It is an amenable number.
1034214012193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1034214012193 is an equidigital number, since it uses as much as digits as its factorization.
1034214012193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
Adding to 1034214012193 its reverse (3912104124301), we get a palindrome (4946318136494).
The spelling of 1034214012193 in words is "one trillion, thirty-four billion, two hundred fourteen million, twelve thousand, one hundred ninety-three".
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