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103431401291849 is a prime number
BaseRepresentation
bin10111100001000111111111…
…111011101100000001001001
3111120012221112012020002010212
4113201013333323230001021
5102024110002212314344
61003551421345050505
730533446354652231
oct2741077773540111
9446187465202125
10103431401291849
112aa5801363a614
12b725847026a35
134593701a8aa37
141b7816c482cc1
15be574c58379e
hex5e11ffeec049

103431401291849 has 2 divisors, whose sum is σ = 103431401291850. Its totient is φ = 103431401291848.

The previous prime is 103431401291819. The next prime is 103431401291887. The reversal of 103431401291849 is 948192104134301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102296232505600 + 1135168786249 = 10114160^2 + 1065443^2 .

It is a cyclic number.

It is not a de Polignac number, because 103431401291849 - 244 = 85839215247433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103431401291797 and 103431401291806.

It is not a weakly prime, because it can be changed into another prime (103431401291819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51715700645924 + 51715700645925.

It is an arithmetic number, because the mean of its divisors is an integer number (51715700645925).

Almost surely, 2103431401291849 is an apocalyptic number.

It is an amenable number.

103431401291849 is a deficient number, since it is larger than the sum of its proper divisors (1).

103431401291849 is an equidigital number, since it uses as much as digits as its factorization.

103431401291849 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 746496, while the sum is 50.

The spelling of 103431401291849 in words is "one hundred three trillion, four hundred thirty-one billion, four hundred one million, two hundred ninety-one thousand, eight hundred forty-nine".