Base | Representation |
---|---|
bin | 11110000110100110001… |
… | …11100111111011000011 |
3 | 10122212210112011120011101 |
4 | 33003103013213323003 |
5 | 113421304020022042 |
6 | 2111055550155231 |
7 | 134504523100555 |
oct | 17032307477303 |
9 | 3585715146141 |
10 | 1034334142147 |
11 | 369727727089 |
12 | 1485644b2b17 |
13 | 766ca575597 |
14 | 380c23454d5 |
15 | 1bd8ab1a6b7 |
hex | f0d31e7ec3 |
1034334142147 has 2 divisors, whose sum is σ = 1034334142148. Its totient is φ = 1034334142146.
The previous prime is 1034334142109. The next prime is 1034334142169. The reversal of 1034334142147 is 7412414334301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1034334142147 - 231 = 1032186658499 is a prime.
It is a super-2 number, since 2×10343341421472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1034334142547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517167071073 + 517167071074.
It is an arithmetic number, because the mean of its divisors is an integer number (517167071074).
Almost surely, 21034334142147 is an apocalyptic number.
1034334142147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1034334142147 is an equidigital number, since it uses as much as digits as its factorization.
1034334142147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 37.
Adding to 1034334142147 its reverse (7412414334301), we get a palindrome (8446748476448).
The spelling of 1034334142147 in words is "one trillion, thirty-four billion, three hundred thirty-four million, one hundred forty-two thousand, one hundred forty-seven".
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