Base | Representation |
---|---|
bin | 10011010001000001… |
… | …11110111000111001 |
3 | 222200211221201210211 |
4 | 21220200332320321 |
5 | 132140403130012 |
6 | 4430211111121 |
7 | 514214354644 |
oct | 115040767071 |
9 | 28624851724 |
10 | 10343411257 |
11 | 4428649a73 |
12 | 2007ba24a1 |
13 | c8aba76ba |
14 | 7019d6a5b |
15 | 4080e46a7 |
hex | 26883ee39 |
10343411257 has 2 divisors, whose sum is σ = 10343411258. Its totient is φ = 10343411256.
The previous prime is 10343411249. The next prime is 10343411317. The reversal of 10343411257 is 75211434301.
10343411257 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5316743056 + 5026668201 = 72916^2 + 70899^2 .
It is a cyclic number.
It is not a de Polignac number, because 10343411257 - 23 = 10343411249 is a prime.
It is not a weakly prime, because it can be changed into another prime (10343411557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5171705628 + 5171705629.
It is an arithmetic number, because the mean of its divisors is an integer number (5171705629).
Almost surely, 210343411257 is an apocalyptic number.
It is an amenable number.
10343411257 is a deficient number, since it is larger than the sum of its proper divisors (1).
10343411257 is an equidigital number, since it uses as much as digits as its factorization.
10343411257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 10343411257 its reverse (75211434301), we get a palindrome (85554845558).
The spelling of 10343411257 in words is "ten billion, three hundred forty-three million, four hundred eleven thousand, two hundred fifty-seven".
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