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10344312220153 is a prime number
BaseRepresentation
bin1001011010000111100100…
…0011100010100111111001
31100121220110220102022001111
42112201321003202213321
52323440122412021103
634000040022520321
72115231462051112
oct226417103424771
940556426368044
1010344312220153
113328aa863316a
1211b09692960a1
135a0606547132
1427a94b427209
1512e12c98386d
hex968790e29f9

10344312220153 has 2 divisors, whose sum is σ = 10344312220154. Its totient is φ = 10344312220152.

The previous prime is 10344312220133. The next prime is 10344312220181. The reversal of 10344312220153 is 35102221344301.

10344312220153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10326916456704 + 17395763449 = 3213552^2 + 131893^2 .

It is a cyclic number.

It is not a de Polignac number, because 10344312220153 - 29 = 10344312219641 is a prime.

It is not a weakly prime, because it can be changed into another prime (10344312220133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5172156110076 + 5172156110077.

It is an arithmetic number, because the mean of its divisors is an integer number (5172156110077).

Almost surely, 210344312220153 is an apocalyptic number.

It is an amenable number.

10344312220153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10344312220153 is an equidigital number, since it uses as much as digits as its factorization.

10344312220153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 10344312220153 its reverse (35102221344301), we get a palindrome (45446533564454).

The spelling of 10344312220153 in words is "ten trillion, three hundred forty-four billion, three hundred twelve million, two hundred twenty thousand, one hundred fifty-three".