Base | Representation |
---|---|
bin | 1001011010001010010001… |
… | …1101000100010011011111 |
3 | 1100121222100122111012201220 |
4 | 2112202210131010103133 |
5 | 2323443120311110444 |
6 | 34000240152504423 |
7 | 2115255512645142 |
oct | 226424435042337 |
9 | 40558318435656 |
10 | 10345040331999 |
11 | 332934163339a |
12 | 11b0b310ab113 |
13 | 5a06c1349c49 |
14 | 27a9b9ddc059 |
15 | 12e17185a619 |
hex | 968a47444df |
10345040331999 has 4 divisors (see below), whose sum is σ = 13793387109336. Its totient is φ = 6896693554664.
The previous prime is 10345040331973. The next prime is 10345040332007. The reversal of 10345040331999 is 99913304054301.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10345040331999 - 221 = 10345038234847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10345040331929) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1724173388664 + ... + 1724173388669.
It is an arithmetic number, because the mean of its divisors is an integer number (3448346777334).
Almost surely, 210345040331999 is an apocalyptic number.
10345040331999 is a deficient number, since it is larger than the sum of its proper divisors (3448346777337).
10345040331999 is an equidigital number, since it uses as much as digits as its factorization.
10345040331999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3448346777336.
The product of its (nonzero) digits is 1574640, while the sum is 51.
The spelling of 10345040331999 in words is "ten trillion, three hundred forty-five billion, forty million, three hundred thirty-one thousand, nine hundred ninety-nine".
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