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1035000118 = 2517500059
BaseRepresentation
bin111101101100001…
…101100100110110
32200010112110020201
4331230031210312
54104430000433
6250411351114
734435233025
oct7554154466
92603473221
101035000118
114912599a9
1224a75249a
13136573009
149b65c8bc
1560ce6a7d
hex3db0d936

1035000118 has 4 divisors (see below), whose sum is σ = 1552500180. Its totient is φ = 517500058.

The previous prime is 1035000107. The next prime is 1035000139. The reversal of 1035000118 is 8110005301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 8110005301 = 62189130409.

It is a junction number, because it is equal to n+sod(n) for n = 1035000095 and 1035000104.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258750028 + ... + 258750031.

It is an arithmetic number, because the mean of its divisors is an integer number (388125045).

Almost surely, 21035000118 is an apocalyptic number.

1035000118 is a deficient number, since it is larger than the sum of its proper divisors (517500062).

1035000118 is an equidigital number, since it uses as much as digits as its factorization.

1035000118 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 517500061.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 1035000118 is about 32171.4177182169. The cubic root of 1035000118 is about 1011.5331803910.

Adding to 1035000118 its reverse (8110005301), we get a palindrome (9145005419).

The spelling of 1035000118 in words is "one billion, thirty-five million, one hundred eighteen", and thus it is an aban number.

Divisors: 1 2 517500059 1035000118