103520434113132 has 24 divisors (see below), whose sum is σ = 242009529859776. Its totient is φ = 34440832762128.

The previous prime is 103520434113127. The next prime is 103520434113139. The reversal of 103520434113132 is 231311434025301.

It is a junction number, because it is equal to n+sod(n) for n = 103520434113093 and 103520434113102.

It is not an unprimeable number, because it can be changed into a prime (103520434113139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8247319578 + ... + 8247332129.

It is an arithmetic number, because the mean of its divisors is an integer number (10083730410824).

Almost surely, 2^{103520434113132} is an apocalyptic number.

103520434113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

103520434113132 is an abundant number, since it is smaller than the sum of its proper divisors (138489095746644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103520434113132 is a wasteful number, since it uses less digits than its factorization.

103520434113132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16494652237 (or 16494652235 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 103520434113132 its reverse (231311434025301), we get a palindrome (334831868138433).

The spelling of 103520434113132 in words is "one hundred three trillion, five hundred twenty billion, four hundred thirty-four million, one hundred thirteen thousand, one hundred thirty-two".