Base | Representation |
---|---|
bin | 110000001101010000… |
… | …1111101001100100011 |
3 | 100220012210021120002002 |
4 | 1200122201331030203 |
5 | 3144004211333011 |
6 | 115320341314215 |
7 | 10323300143654 |
oct | 1403241751443 |
9 | 326183246062 |
10 | 103524324131 |
11 | 3a9a4866a78 |
12 | 1809210596b |
13 | 99baa14737 |
14 | 502115152b |
15 | 2a5d84dc3b |
hex | 181a87d323 |
103524324131 has 2 divisors, whose sum is σ = 103524324132. Its totient is φ = 103524324130.
The previous prime is 103524324121. The next prime is 103524324143. The reversal of 103524324131 is 131423425301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103524324131 - 230 = 102450582307 is a prime.
It is a super-2 number, since 2×1035243241312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103524324094 and 103524324103.
It is not a weakly prime, because it can be changed into another prime (103524324121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51762162065 + 51762162066.
It is an arithmetic number, because the mean of its divisors is an integer number (51762162066).
Almost surely, 2103524324131 is an apocalyptic number.
103524324131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103524324131 is an equidigital number, since it uses as much as digits as its factorization.
103524324131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 103524324131 its reverse (131423425301), we get a palindrome (234947749432).
The spelling of 103524324131 in words is "one hundred three billion, five hundred twenty-four million, three hundred twenty-four thousand, one hundred thirty-one".
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