Base | Representation |
---|---|
bin | 11110001000010010100… |
… | …11111110100010000111 |
3 | 10122222010220000010001220 |
4 | 33010021103332202013 |
5 | 113430134244201101 |
6 | 2111330105451423 |
7 | 134536203200013 |
oct | 17041123764207 |
9 | 3588126003056 |
10 | 1035243350151 |
11 | 36a05397855a |
12 | 148778aa0b73 |
13 | 76813a4419a |
14 | 3816adbb543 |
15 | 1bde0865636 |
hex | f1094fe887 |
1035243350151 has 16 divisors (see below), whose sum is σ = 1381149685728. Its totient is φ = 689749760000.
The previous prime is 1035243350123. The next prime is 1035243350161. The reversal of 1035243350151 is 1510533425301.
1035243350151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 1035243350151 - 227 = 1035109132423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1035243350161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38648275 + ... + 38675051.
It is an arithmetic number, because the mean of its divisors is an integer number (86321855358).
Almost surely, 21035243350151 is an apocalyptic number.
1035243350151 is a deficient number, since it is larger than the sum of its proper divisors (345906335577).
1035243350151 is a wasteful number, since it uses less digits than its factorization.
1035243350151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34002.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 1035243350151 its reverse (1510533425301), we get a palindrome (2545776775452).
The spelling of 1035243350151 in words is "one trillion, thirty-five billion, two hundred forty-three million, three hundred fifty thousand, one hundred fifty-one".
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