10354124133 has 40 divisors (see below), whose sum is σ = 15913713816. Its totient is φ = 6704985600.

The previous prime is 10354124129. The next prime is 10354124161. The reversal of 10354124133 is 33142145301.

It is a happy number.

10354124133 is a `hidden beast` number, since 103 + 541 + 2 + 4 + 13 + 3 = 666.

10354124133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 698703489 + 9655420644 = 26433^2 + 98262^2 .

It is not a de Polignac number, because 10354124133 - 2² = 10354124129 is a prime.

It is a super-3 number, since 3×10354124133³ (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 10354124097 and 10354124106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10354124633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 767103 + ... + 780483.

Almost surely, 2^10354124133 is an apocalyptic number.

It is an amenable number.

10354124133 is a deficient number, since it is larger than the sum of its proper divisors (5559589683).

10354124133 is a wasteful number, since it uses less digits than its factorization.

10354124133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13667 (or 13658 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 10354124133 its reverse (33142145301), we get a palindrome (43496269434).

The spelling of 10354124133 in words is "ten billion, three hundred fifty-four million, one hundred twenty-four thousand, one hundred thirty-three".