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103541252254014 = 23154671115722207
BaseRepresentation
bin10111100010101110010011…
…100011110110100100111110
3111120121110001220012011001010
4113202232103203312210332
5102032404441034112024
61004114110012300050
730544415516511111
oct2742562343664476
9446543056164033
10103541252254014
112aa9a664645363
12b742ba3a71626
1345a0b8a434973
141b7d5cd94c578
15be852b53bb29
hex5e2b938f693e

103541252254014 has 16 divisors (see below), whose sum is σ = 207095893360128. Its totient is φ = 34511519275992.

The previous prime is 103541252254001. The next prime is 103541252254039. The reversal of 103541252254014 is 410452252145301.

It is a super-3 number, since 3×1035412522540143 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 557768302 + ... + 557953905.

It is an arithmetic number, because the mean of its divisors is an integer number (12943493335008).

Almost surely, 2103541252254014 is an apocalyptic number.

103541252254014 is an abundant number, since it is smaller than the sum of its proper divisors (103554641106114).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103541252254014 is a wasteful number, since it uses less digits than its factorization.

103541252254014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1115737679.

The product of its (nonzero) digits is 192000, while the sum is 39.

The spelling of 103541252254014 in words is "one hundred three trillion, five hundred forty-one billion, two hundred fifty-two million, two hundred fifty-four thousand, fourteen".

Divisors: 1 2 3 6 15467 30934 46401 92802 1115722207 2231444414 3347166621 6694333242 17256875375669 34513750751338 51770626127007 103541252254014