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10355710993 is a prime number
BaseRepresentation
bin10011010010011111…
…11001110000010001
3222201201002121212121
421221033321300101
5132202030222433
64431330454241
7514424043145
oct115117716021
928651077777
1010355710993
11443458aa41
122010134381
13c905c2c54
147034b9225
15409223c2d
hex2693f9c11

10355710993 has 2 divisors, whose sum is σ = 10355710994. Its totient is φ = 10355710992.

The previous prime is 10355710987. The next prime is 10355711039. The reversal of 10355710993 is 39901755301.

10355710993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9156958864 + 1198752129 = 95692^2 + 34623^2 .

It is a cyclic number.

It is not a de Polignac number, because 10355710993 - 225 = 10322156561 is a prime.

It is a super-3 number, since 3×103557109933 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10355710903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177855496 + 5177855497.

It is an arithmetic number, because the mean of its divisors is an integer number (5177855497).

Almost surely, 210355710993 is an apocalyptic number.

It is an amenable number.

10355710993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10355710993 is an equidigital number, since it uses as much as digits as its factorization.

10355710993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 127575, while the sum is 43.

The spelling of 10355710993 in words is "ten billion, three hundred fifty-five million, seven hundred ten thousand, nine hundred ninety-three".