1040130441131 has 2 divisors, whose sum is σ = 1040130441132. Its totient is φ = 1040130441130.

The previous prime is 1040130441101. The next prime is 1040130441143. The reversal of 1040130441131 is 1311440310401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1040130441131 - 2³⁴ = 1022950571947 is a prime.

It is a super-2 number, since 2×1040130441131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1040130441097 and 1040130441106.

It is not a weakly prime, because it can be changed into another prime (1040130441101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520065220565 + 520065220566.

It is an arithmetic number, because the mean of its divisors is an integer number (520065220566).

Almost surely, 2^{1040130441131} is an apocalyptic number.

1040130441131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040130441131 is an equidigital number, since it uses as much as digits as its factorization.

1040130441131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1040130441131 its reverse (1311440310401), we get a palindrome (2351570751532).

The spelling of 1040130441131 in words is "one trillion, forty billion, one hundred thirty million, four hundred forty-one thousand, one hundred thirty-one".