Base | Representation |
---|---|
bin | 11110010001011011111… |
… | …10110011110010011001 |
3 | 10200102211002100212020111 |
4 | 33020231332303302121 |
5 | 114020213300303101 |
6 | 2113501231524321 |
7 | 135101655041524 |
oct | 17105576636231 |
9 | 3612732325214 |
10 | 1040153525401 |
11 | 371143603931 |
12 | 1497093896a1 |
13 | 771170b2823 |
14 | 384b5179bbb |
15 | 1c0cb977251 |
hex | f22dfb3c99 |
1040153525401 has 2 divisors, whose sum is σ = 1040153525402. Its totient is φ = 1040153525400.
The previous prime is 1040153525309. The next prime is 1040153525413. The reversal of 1040153525401 is 1045253510401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 731127603600 + 309025921801 = 855060^2 + 555901^2 .
It is an emirp because it is prime and its reverse (1045253510401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1040153525401 - 215 = 1040153492633 is a prime.
It is not a weakly prime, because it can be changed into another prime (1040153525491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520076762700 + 520076762701.
It is an arithmetic number, because the mean of its divisors is an integer number (520076762701).
Almost surely, 21040153525401 is an apocalyptic number.
It is an amenable number.
1040153525401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1040153525401 is an equidigital number, since it uses as much as digits as its factorization.
1040153525401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 1040153525401 in words is "one trillion, forty billion, one hundred fifty-three million, five hundred twenty-five thousand, four hundred one".
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