104020131331 has 2 divisors, whose sum is σ = 104020131332. Its totient is φ = 104020131330.

The previous prime is 104020131289. The next prime is 104020131343. The reversal of 104020131331 is 133131020401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104020131331 - 2⁷ = 104020131203 is a prime.

It is a super-2 number, since 2×104020131331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 104020131299 and 104020131308.

It is not a weakly prime, because it can be changed into another prime (104020131731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52010065665 + 52010065666.

It is an arithmetic number, because the mean of its divisors is an integer number (52010065666).

Almost surely, 2^104020131331 is an apocalyptic number.

104020131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

104020131331 is an equidigital number, since it uses as much as digits as its factorization.

104020131331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 104020131331 its reverse (133131020401), we get a palindrome (237151151732).

The spelling of 104020131331 in words is "one hundred four billion, twenty million, one hundred thirty-one thousand, three hundred thirty-one".