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10402300214491 is a prime number
BaseRepresentation
bin1001011101011111100101…
…1010001011110011011011
31100211110011012001121220111
42113113321122023303123
52330412402323330431
634042430054505151
72122353460632103
oct227277132136333
940743135047814
1010402300214491
113350655313629
1212000513651b7
135a5c181b5513
1427d68c9b8203
151308c37517b1
hex975f968bcdb

10402300214491 has 2 divisors, whose sum is σ = 10402300214492. Its totient is φ = 10402300214490.

The previous prime is 10402300214473. The next prime is 10402300214521. The reversal of 10402300214491 is 19441200320401.

It is a weak prime.

It is an emirp because it is prime and its reverse (19441200320401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10402300214491 - 27 = 10402300214363 is a prime.

It is not a weakly prime, because it can be changed into another prime (10402303214491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5201150107245 + 5201150107246.

It is an arithmetic number, because the mean of its divisors is an integer number (5201150107246).

Almost surely, 210402300214491 is an apocalyptic number.

10402300214491 is a deficient number, since it is larger than the sum of its proper divisors (1).

10402300214491 is an equidigital number, since it uses as much as digits as its factorization.

10402300214491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 10402300214491 its reverse (19441200320401), we get a palindrome (29843500534892).

The spelling of 10402300214491 in words is "ten trillion, four hundred two billion, three hundred million, two hundred fourteen thousand, four hundred ninety-one".