104024113 has 4 divisors (see below), whose sum is σ = 106237440. Its totient is φ = 101810788.

The previous prime is 104024111. The next prime is 104024143. The reversal of 104024113 is 311420401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311420401 = 7433 ⋅41897.

It is a cyclic number.

It is not a de Polignac number, because 104024113 - 2¹ = 104024111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104024111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1106593 + ... + 1106686.

It is an arithmetic number, because the mean of its divisors is an integer number (26559360).

Almost surely, 2^104024113 is an apocalyptic number.

It is an amenable number.

104024113 is a deficient number, since it is larger than the sum of its proper divisors (2213327).

104024113 is an equidigital number, since it uses as much as digits as its factorization.

104024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2213326.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 104024113 is about 10199.2211957580. The cubic root of 104024113 is about 470.3032794365.

Adding to 104024113 its reverse (311420401), we get a palindrome (415444514).

The spelling of 104024113 in words is "one hundred four million, twenty-four thousand, one hundred thirteen".