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1040255464433 is a prime number
BaseRepresentation
bin11110010001101000000…
…11101011001111110001
310200110002012011220022012
433020310003223033301
5114020420344330213
62113515312452305
7135104333361053
oct17106403531761
93613065156265
101040255464433
113711960aa169
1214973754a095
1377132254a93
14384c49138d3
151c0d58b14a8
hexf2340eb3f1

1040255464433 has 2 divisors, whose sum is σ = 1040255464434. Its totient is φ = 1040255464432.

The previous prime is 1040255464411. The next prime is 1040255464439. The reversal of 1040255464433 is 3344645520401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 693584155489 + 346671308944 = 832817^2 + 588788^2 .

It is a cyclic number.

It is not a de Polignac number, because 1040255464433 - 212 = 1040255460337 is a prime.

It is a super-2 number, since 2×10402554644332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1040255464439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520127732216 + 520127732217.

It is an arithmetic number, because the mean of its divisors is an integer number (520127732217).

Almost surely, 21040255464433 is an apocalyptic number.

It is an amenable number.

1040255464433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040255464433 is an equidigital number, since it uses as much as digits as its factorization.

1040255464433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 41.

The spelling of 1040255464433 in words is "one trillion, forty billion, two hundred fifty-five million, four hundred sixty-four thousand, four hundred thirty-three".