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104032015153 = 119457455923
BaseRepresentation
bin110000011100011001…
…0101001001100110001
3100221112011120221020021
41200320302221030301
53201024143441103
6115442555043441
710342003352503
oct1407062511461
9327464527207
10104032015153
11401353a6830
12181b4140581
139a6bc60421
14506c749d73
152a8d1d5bbd
hex1838ca9331

104032015153 has 4 divisors (see below), whose sum is σ = 113489471088. Its totient is φ = 94574559220.

The previous prime is 104032015133. The next prime is 104032015169. The reversal of 104032015153 is 351510230401.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104032015153 - 25 = 104032015121 is a prime.

It is a super-2 number, since 2×1040320151532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104032015133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4728727951 + ... + 4728727972.

It is an arithmetic number, because the mean of its divisors is an integer number (28372367772).

Almost surely, 2104032015153 is an apocalyptic number.

It is an amenable number.

104032015153 is a deficient number, since it is larger than the sum of its proper divisors (9457455935).

104032015153 is an equidigital number, since it uses as much as digits as its factorization.

104032015153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9457455934.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 104032015153 its reverse (351510230401), we get a palindrome (455542245554).

The spelling of 104032015153 in words is "one hundred four billion, thirty-two million, fifteen thousand, one hundred fifty-three".

Divisors: 1 11 9457455923 104032015153