Base | Representation |
---|---|
bin | 11110010001110000010… |
… | …01010101000111011010 |
3 | 10200110020222020200120121 |
4 | 33020320021111013122 |
5 | 114021040424234024 |
6 | 2113530202543454 |
7 | 135106125366052 |
oct | 17107011250732 |
9 | 3613228220517 |
10 | 1040324055514 |
11 | 371220898707 |
12 | 149756507b8a |
13 | 7714351c213 |
14 | 384cda8a562 |
15 | 1c0db90e8e4 |
hex | f2382551da |
1040324055514 has 4 divisors (see below), whose sum is σ = 1560486083274. Its totient is φ = 520162027756.
The previous prime is 1040324055487. The next prime is 1040324055539. The reversal of 1040324055514 is 4155504230401.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 659641225489 + 380682830025 = 812183^2 + 616995^2 .
It is a super-3 number, since 3×10403240555143 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1040324055514.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260081013877 + ... + 260081013880.
Almost surely, 21040324055514 is an apocalyptic number.
1040324055514 is a deficient number, since it is larger than the sum of its proper divisors (520162027760).
1040324055514 is an equidigital number, since it uses as much as digits as its factorization.
1040324055514 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 520162027759.
The product of its (nonzero) digits is 48000, while the sum is 34.
Adding to 1040324055514 its reverse (4155504230401), we get a palindrome (5195828285915).
The spelling of 1040324055514 in words is "one trillion, forty billion, three hundred twenty-four million, fifty-five thousand, five hundred fourteen".
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