Base | Representation |
---|---|
bin | 11110010001110001001… |
… | …01000001000010010101 |
3 | 10200110021110220102101112 |
4 | 33020320211001002111 |
5 | 114021044304011201 |
6 | 2113531022304405 |
7 | 135106244154560 |
oct | 17107045010225 |
9 | 3613243812345 |
10 | 1040331313301 |
11 | 3712249a5585 |
12 | 149758a28105 |
13 | 77144b90877 |
14 | 384d0a194d7 |
15 | 1c0dc3950bb |
hex | f238941095 |
1040331313301 has 4 divisors (see below), whose sum is σ = 1188950072352. Its totient is φ = 891712554252.
The previous prime is 1040331313297. The next prime is 1040331313321. The reversal of 1040331313301 is 1033131330401.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1040331313301 - 22 = 1040331313297 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1040331313321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74309379515 + ... + 74309379528.
It is an arithmetic number, because the mean of its divisors is an integer number (297237518088).
Almost surely, 21040331313301 is an apocalyptic number.
It is an amenable number.
1040331313301 is a deficient number, since it is larger than the sum of its proper divisors (148618759051).
1040331313301 is an equidigital number, since it uses as much as digits as its factorization.
1040331313301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148618759050.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1040331313301 its reverse (1033131330401), we get a palindrome (2073462643702).
The spelling of 1040331313301 in words is "one trillion, forty billion, three hundred thirty-one million, three hundred thirteen thousand, three hundred one".
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